#include<bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
int n, m, a[N], dp[N][25], dp2[N][25];
int main() {
	scanf("%d %d", &n, &m);
	
	for(int i = 1; i <= n; i++) scanf("%d", &a[i]);
	
	for(int i = 1; i <= n; i++) {
		dp[i][0] = a[i] ;
		dp2[i][0] = a[i] ;
	}
	
	for(int i = 1; (1 << i) < n; i++) {
		for(int j = 1; j + (1 << i) - 1 <= n; j++) {
			dp[j][i] = max(dp[j][i - 1], dp[j + (1 << i - 1)][i - 1]);
			dp2[j][i] = min(dp2[j][i - 1], dp2[j + (1 << i - 1)][i - 1]);
		}
	}
	int t = log2(m);
	for(int i = 1; i + m - 1 <= n; i++) {
		printf("%d ", max(dp[i][t], dp[i + m - (1 << t)][t]));
		printf("%d\n", min(dp2[i][t], dp2[i + m - (1 << t)][t]));
	}
	return 0;
}


1 条评论

  • @ 2025-4-24 19:17:31

    没过!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

    • 1

    信息

    ID
    1364
    时间
    1000ms
    内存
    256MiB
    难度
    6
    标签
    (无)
    递交数
    94
    已通过
    32
    上传者